Lattice enthalpy for $NaCl$ is $+788\, \text{kJ}\, \text{mol}^{-1}$ and $\Delta H_{\text{hydration}}^{\circ} = -784\, \text{kJ}\, \text{mol}^{-1}$. The enthalpy of solution of $NaCl$ is:

Question

$-572\, \text{kJ}\, \text{mol}^{-1}$

$-4\, \text{kJ}\, \text{mol}^{-1}$

+$572\, \text{kJ}\, \text{mol}^{-1}$

+$4\, \text{kJ}\, \text{mol}^{-1}$

Solution

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