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Question

Consider the following 4 electrodes: $A: Ag^{+} (0.0001 \, \text{M}) / Ag(s)$ $B: Ag^{+} (0.1 \, \text{M}) / Ag(s)$ $C: Ag^{+} (0.01 \, \text{M}) / Ag(s)$ $D: Ag^{+} (0.001 \, \text{M}) / Ag(s)$ $E^{\circ}_{Ag^{+}/Ag} = +0.80 \, \text{V}$ Then arrange the electrodes in the order of their reduction potentials in volts.

$A > D > C > B$

$A > B > C > D$

$B > C > D > A$

$C > D > A > B$

Solution

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