If $f(x) = 1 + nx + \frac{n(n-1)}{2}x^2 + \frac{n(n-1)(n-2)}{6}x^3 + \ldots + x^n$ , then $f^{\prime}(1) =$

Question

If $f(x) = 1 + nx + \frac{n(n-1)}{2}x^2 + \frac{n(n-1)(n-2)}{6}x^3 + \ldots + x^n$

, then $f^{\prime}(1) =$

$n(n - 1)2^{n}$

$2^{n - 1}$

$(n - 1)2^{n-1}$

$n(n - 1)2^{n - 2}$

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