If $A = \begin{bmatrix}1 & \tan \frac{\alpha}{2} \\ -\tan \frac{\alpha}{2} & 1\end{bmatrix}$ and $AB = I$, then $B = $

Question

$(\cos^2 \frac{\alpha}{2} \cdot I)$

$(\sin^2 \frac{\alpha}{2} \cdot A)$

$(\cos^2 \frac{\alpha}{2} \cdot A^{T})$

$(\cos^2 \frac{\alpha}{2} \cdot A)$

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