Question
A particle moves along the curve $\frac{x^2}{16} + \frac{y^2}{4} = 1$. When the rate of change of the abscissa is 4 times that of the ordinate, then the quadrants in which the particle lies are
A particle moves along the curve $\frac{x^2}{16} + \frac{y^2}{4} = 1$. When the rate of change of the abscissa is 4 times that of the ordinate, then the quadrants in which the particle lies are