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Question

If $f(x)$ and $g(x)$ are two functions with $g(x) = x - \frac{1}{x}$ and $f \circ g(x) = x^3 - \frac{1}{x^3}$, then $f^{\prime}(x) =$

$x^2 - \frac{1}{x^2}$

$1 - \frac{1}{x^2}$

$3x^2 + 3$

$3x^2 + \frac{3}{x^4}$

Solution

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