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Question

The distance $s$ in meters traveled by a particle in $t$ seconds is given by $s = \frac{2 t^3}{3} - 18 t + \frac{5}{3}$. The acceleration when the particle comes to rest is?

$12\, \frac{m}{s^{2}}$

$18\, \frac{m}{s^{2}}$

$3\, \frac{m}{s^{2}}$

$10\, \frac{m}{s^{2}}$

Solution

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