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Question

If $A$ and $B$ are events such that $P(A) = \frac{1}{4}$, $P(A \mid B) = \frac{1}{2}$, and $P(B \mid A) = \frac{2}{3}$, then $P(B)$ is

$\frac{2}{3}$

$\frac{1}{2}$

$\frac{1}{6}$

$\frac{1}{3}$

Solution

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