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Question

Let the relation $R$ be defined in $\mathbb{N}$ by $aRb$ if $3a + 2b = 27$. Then $R$ is

{$ \{(1,2),(3,9),(5,6),(7,3),(9,0)\}$}

{$ \{(2,1),(9,3),(6,5),(3,7)\}$}

{$ \{(1,12),(3,9),(5,6),(7,3)\}$}

{$ \left\{\left(0, \frac{27}{2}\right),(1,12),(3,9),(5,6),(7,3)\right\}$}

Solution

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