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Question

If unit vectors $\vec{a}$ and $\vec{b}$ are inclined at an angle $2\theta$ such that $\left|\vec{a} - \vec{b}\right| < 1$ and $0 \leq \theta \leq \pi$, then $\theta$ lies in the interval:

$[0, \frac{\pi}{6}) \cup (\frac{5\pi}{6}, \pi]$

$[0, \pi]$

$[\frac{\pi}{6}, \frac{\pi}{2}]$

$[\frac{\pi}{2}, \frac{5\pi}{6}]$

Solution

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