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Question

Consider a pyramid OPQRS located in the first octant $(x \geq 0, y \geq 0, z \geq 0)$ with O as the origin and OP along the X-axis and OR along the Y-axis, respectively. The base OPQRS of the pyramid is a square with $OP=3$. The point S is directly above the midpoint T of diagonal OQ such that $TS=3$. Then,

$\frac{\pi}{3}$

$\frac{\pi}{6}$

$\cos^{-1}\left(\frac{1}{\sqrt{3}}\right)$

$\cos^{-1}\left(\frac{1}{3}\right)$

Solution

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