Question
If $\vec{a}$ and $\vec{b}$ are unit vectors such that $|\vec{a} + \vec{b}| = 1$ and $|\vec{a} - \vec{b}| = \sqrt{3}$, then $|3\vec{a} + 2\vec{b}| =$
If $\vec{a}$ and $\vec{b}$ are unit vectors such that $|\vec{a} + \vec{b}| = 1$ and $|\vec{a} - \vec{b}| = \sqrt{3}$, then $|3\vec{a} + 2\vec{b}| =$