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Question

Prove that $\left( \vec{a} \cdot \hat{i} \right) \left( \vec{a} \times \hat{i} \right) + \left( \vec{a} \cdot \hat{j} \right) \left( \vec{a} \times \hat{j} \right) + \left( \vec{a} \cdot \hat{k} \right) \left( \vec{a} \times \hat{k} \right) = \vec{0}$

$3\vec{a}$

$\vec{a}$

$\vec{0}$

$2\vec{a}$

Solution

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