The number of unit vectors perpendicular to the plane of vectors $\vec{a} = 2\hat{i} - 6\hat{j} - 3\hat{k}$ and $\vec{b} = 4\hat{i} + 3\hat{j} - \hat{k}$ is/are

Question

$\frac{1}{\sqrt{26}}(4\hat{i} + 3\hat{j} - \hat{k})$

$\frac{1}{7}(2\hat{i} - 6\hat{j} - 3\hat{k})$

$\frac{1}{7}(3\hat{i} + 2\hat{j} + 6\hat{k})$

$\frac{1}{7}(2\hat{i} - 3\hat{j} - 6\hat{k})$

Solution

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