Question
If the diagonals of a parallelogram are represented by the vectors $\vec{d_1} = 3\hat{i} + \hat{j} - 2\hat{k}$ and $\vec{d_2} = \hat{i} + 3\hat{j} - 4\hat{k}$, then its area in square units is
If the diagonals of a parallelogram are represented by the vectors $\vec{d_1} = 3\hat{i} + \hat{j} - 2\hat{k}$ and $\vec{d_2} = \hat{i} + 3\hat{j} - 4\hat{k}$, then its area in square units is