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Question

Let $\vec{a}$, $\vec{b}$, and $\vec{c}$ be unit vectors such that $\vec{a} \cdot \vec{b} = 0 = \vec{a} \cdot \vec{c}$. If the angle between $\vec{b}$ and $\vec{c}$ is $\frac{\pi}{6}$, then find $\vec{a}$.

$ \pm 2 (\vec{b} \times \vec{c}) $

$ 2 (\vec{b} \times \vec{c}) $

$ \pm \frac{1}{2} (\vec{b} \times \vec{c}) $

$ -\frac{1}{2} (\vec{b} \times \vec{c}) $

Solution

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