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Question

The length of the longer diagonal of the parallelogram constructed on the vectors $5\vec{a} + 2\vec{b}$ and $\vec{a} - 3\vec{b}$, if it is given that $|\vec{a}| = 2\sqrt{2}$, $|\vec{b}| = 3$, and $\vec{a} \cdot \vec{b} = \frac{\pi}{4}$ is:

15

$\sqrt{3}$

$\sqrt{593}$

$\sqrt{369}$

Solution

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