Let $\vec{a}$, $\vec{b}$, $\vec{c}$ represent respectively $\overrightarrow{BC}$, $\overrightarrow{CA}$, and $\overrightarrow{AB}$ where ABC is a triangle. Then,

Question

$\vec{a} + \vec{b} = \vec{c}$

$\vec{b} + \vec{c} = \vec{a}$

$\vec{a} \times \vec{b} = \vec{b} \times \vec{c} = \vec{c} \times \vec{a}$

$[\vec{a} \vec{b} \vec{c}] = [\vec{b} \vec{c} \vec{a}] = [\vec{c} \vec{a} \vec{b}] \neq 0$

Solution

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