Question
Let $a$, $b$, $c$ denote the lengths of the sides of a triangle such that $(a-b)\vec{u} + (b-c)\vec{v} + (c-a)(\vec{u} \times \vec{v}) = \vec{0}$. For any two non-collinear vectors $\vec{u}$ and $\vec{v}$, the triangle is
Let $a$, $b$, $c$ denote the lengths of the sides of a triangle such that $(a-b)\vec{u} + (b-c)\vec{v} + (c-a)(\vec{u} \times \vec{v}) = \vec{0}$. For any two non-collinear vectors $\vec{u}$ and $\vec{v}$, the triangle is