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Question

An electromagnetic wave is travelling in x-direction with electric field vector given by

\(\vec{E}_{y}=E_{0}\sin(kx-\omega t)\hat{j} \) . The correct expression for magnetic field vector is

 

\(\vec{B}_{z}=E_{0}C\sin(kx-\omega t)\hat{k} \)

\(\vec{B}_{z}=\frac{E_{0}}{C}\sin(kx-\omega t)\hat{k} \)

\(\vec{B}_{y}=E_{0}C\sin(kx-\omega t)\hat{j} \)

\(\vec{B}_{y}=\frac{E_{0}}{C}\sin(kx-\omega t)\hat{j} \)

Solution

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