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Question

Let $x=\frac{m}{n}$ ($m, n$ are co-prime natural numbers) be a solution of the equation $\cos \left(2 \sin ^{-1} x\right)=\frac{1}{9}$ and let $\alpha, \beta(\alpha >\beta)$ be the roots of the equation $m x^2-n x-m+ n=0$. Then the point $(\alpha, \beta)$ lies on the line

$3 x-2 y=-2$
$3 x+2 y=2$
$5 x+8 y=9$
$5 x-8 y=-9$

Solution

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