A small liquid drop of radius $R$ is divided into 27 identical liquid drops. If the surface tension is $T$, then the work done in the process will be:

Question

$4 \pi \mathrm{R}^2 \mathrm{~T}$

$8 \pi R^2 \mathrm{~T}$

$\frac{1}{8} \pi R^2 T$

$3 \pi R^2 \mathrm{~T}$

Solution

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