A particle is moving in a straight line. The variation of position '$x$' as a function of time '$t$' is given as $x=\left(t^3-6 t^2+20 t+15\right) m$. The velocity of the body when its acceleration becomes zero is :
#39; as a function of time '$t#39; is given as $x=\lef. Tags and topics: JEE MAIN,JEE Advanced,JEE Mains,KCET,Motion in a Straight Line,One Dimensional Motion - Non-uniform Acceleration,NCERT,NEET, JEE Main Physics,Class 11 Physics,Class 12 Physics."> #39; as a function of time '$t#39; is given as $x=\lef. Tags and topics: JEE MAIN,JEE Advanced,JEE Mains,KCET,Motion in a Straight Line,One Dimensional Motion - Non-uniform Acceleration,NCERT,NEET, JEE Main Physics,Class 11 Physics,Class 12 Physics."> #39; as a function of time '$t#39; is given as $x=\lef. Tags and topics: JEE MAIN,JEE Advanced,JEE Mains,KCET,Motion in a Straight Line,One Dimensional Motion - Non-uniform Acceleration,NCERT,NEET, JEE Main Physics,Class 11 Physics,Class 12 Physics.">
A particle is moving in a straight line. The variation of position '$x$' as a function of time '$t$' is given as $x=\left(t^3-6 t^2+20 t+15\right) m$. The velocity of the body when its acceleration becomes zero is :