If e1 be the eccentricity of the conic 9x2+4y2=36 and e2 is the eccentricity of the conic 9x2-4y2=36 and e3 be the eccentricity of conic x2-y2=36 then 18e12+e22·e32 is equal to -

Question

e_{1}

be the eccentricity of the conic

9 x^{2} + 4 y^{2} = 36

and

e_{2}

is the eccentricity of the conic

9 x^{2} - 4 y^{2} = 36

and

e_{3}

be the eccentricity of conic

x^{2} - y^{2} = 36

then

18 (e_{1}^{2} + e_{2}^{2}) \cdot e_{3}^{2}

is equal to -

Correct Answer

137

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