Two spherical soap bubbles of radii r1 and r2 in vacuum coalesce under isothermal conditions. The resulting bubble has a radius R such that,

Question

Two spherical soap bubbles of radii $r_{1}$ and $r_{2}$ in vacuum coalesce under isothermal conditions. The resulting bubble has a radius $R$ such that,

R = \frac{(r_{1} + r_{2})}{2}

R = [\frac{T_{1} T_{2}}{(r_{1} + r_{2})}]

R = \sqrt{(r_{1}^{2} + r_{2}^{2})}

R = r_{1} + r_{2}

Solution

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