Bond dissociation enthalpy of E—H (E = element) bonds is given below. Which of the compounds will act as strongest reducing agent? Compound NH3 PH3 AsH3 SbH3 △diss (E—H)/kJ mol–1 389 322 297 255

Question

Bond dissociation enthalpy of

E — H (E = element)

bonds is given below. Which of the compounds will act as strongest reducing agent?

Compound	${NH}_{3}$	${PH}_{3}$	${AsH}_{3}$	${SbH}_{3}$
$△_{diss} (E — H) / kJ {mol}^{- 1}$	$389$	$322$	$297$	$255$

{NH}_{3}

{PH}_{3}

{AsH}_{3}

{SbH}_{3}

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