The value of ′n′ In the reaction, Cr2O72-+14H++nFe2+⟶2Cr3++nFe3++7H2O will be

Question

The value of

' n'

In the reaction,

{Cr}_{2} O_{7}^{2 -} + 14 H^{+} + {nFe}^{2 +} ⟶ 2 {Cr}^{3 +} + {nFe}^{3 +} + 7 H_{2} O

will be

2

3

6

7

Please login to view the detailed solution steps...