The logarithm of equilibrium constant for the reaction ${\mathrm{Pd}}^{2+}+4{\mathrm{Cl}}^{-}\rightleftharpoons {\mathrm{PdCl}}_4^{2-}$ is
(Nearest integer)

Given: $\frac{2.303\mathrm{RT}}{\mathrm{F}}=0.06 \mathrm{V}$

${\mathrm{Pd}}_{\left(\mathrm{aq}\right)}^{2+}+2{\mathrm{e}}^{-}\rightleftharpoons \mathrm{Pd}\left(\mathrm{s}\right) {\mathrm{E}}^o=0.83 \mathrm{V}$

${\mathrm{PdCl}}_4^{2-}\left(\mathrm{aq}\right)+2{\mathrm{e}}^{-}\rightleftharpoons \mathrm{Pd}\left(\mathrm{s}\right)+4{\mathrm{Cl}}^{-}\left(\mathrm{aq}\right)$

${\mathrm{E}}^{\mathrm{o}}=0.65 \mathrm{V}$