If ∫022x-2x-x2dx= ∫011-1-y2-y22dy+∫122-y22dy+I, then I equal to

Question

If $\int_{0}^{2} (\sqrt{2 x} - \sqrt{2 x - x^{2}}) d x =$

$\int_{0}^{1} (1 - \sqrt{1 - y^{2}} - \frac{y^{2}}{2}) d y + \int_{1}^{2} (2 - \frac{y^{2}}{2}) d y + I$ , then $I$ equal to

\int_{0}^{1} (1 + \sqrt{1 - y^{2}}) d y

\int_{0}^{1} (\frac{y^{2}}{2} - \sqrt{1 - y^{2}} + 1) d y

\int_{0}^{1} (1 - \sqrt{1 - y^{2}}) d y

\int_{0}^{1} (\frac{y^{2}}{2} + \sqrt{1 - y^{2}} + 1) d y

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