If $\mathrm{R}$ is the radius of the earth and the acceleration due to gravity on the surface of earth is $g=\pi^2 \mathrm{~m} / \mathrm{s}^2$, then the length of the second's pendulum at a height $\mathrm{h}=2 R$ from the surface of earth will be, :

Question

$\frac{1}{9} \mathrm{~m}$

$\frac{8}{9} \mathrm{~m}$

$\frac{2}{9} \mathrm{~m}$

$\frac{4}{9} \mathrm{~m}$

Solution

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