A galvanometer has a resistance of $50 ~\Omega$ and it allows maximum current of $5 \mathrm{~mA}$. It can be converted into voltmeter to measure upto $100 \mathrm{~V}$ by connecting in series a resistor of resistance :
$19500 \Omega$
$5975 \Omega$
$20050 \Omega$
$19950 \Omega$
Solution
Please login to view the detailed solution steps...