Two identical capacitors have same capacitance $C$. One of them is charged to the potential $V$ and other to the potential $2 \mathrm{~V}$. The negative ends of both are connected together. When the positive ends are also joined together, the decrease in energy of the combined system is :
$\frac{1}{4} \mathrm{CV}^2$
$\frac{3}{4} \mathrm{CV}^2$
$\frac{1}{2} \mathrm{CV}^2$
$2 \mathrm{CV}^2$
Solution
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