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Question

The four quantum numbers for the electron in the outer most orbital of potassium (atomic no. 19) are

$\mathrm{n}=3, l=0, \mathrm{~m}=1, \mathrm{~s}=+\frac{1}{2}$
$\mathrm{n}=4, l=0, \mathrm{~m}=0, s=+\frac{1}{2}$
$\mathrm{n}=2, l=0, \mathrm{~m}=0, s=+\frac{1}{2}$
$\mathrm{n}=4, l=2, \mathrm{~m}=-1, s=+\frac{1}{2}$

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