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Question

A block of mass $5 \mathrm{~kg}$ is placed on a rough inclined surface as shown in the figure. If $\overrightarrow{F_1}$ is the force required to just move the block up the inclined plane and $\overrightarrow{F_2}$ is the force required to just prevent the block from sliding down, then the value of $\left|\overrightarrow{F_1}\right|-\left|\overrightarrow{F_2}\right|$ is : [Use $\left.\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2\right]$

$5 \sqrt{3} N$
$\frac{5 \sqrt{3}}{2} N$
$10 \mathrm{~N}$
$25 \sqrt{3} N$

Solution

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