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Question

If two vectors $\vec{A}$ and $\vec{B}$ having equal magnitude $R$ are inclined at angle $\theta$, then

$|\vec{A}+\vec{B}|=2 R \cos \left(\frac{\theta}{2}\right)$
$|\vec{A}-\vec{B}|=2 R \cos \left(\frac{\theta}{2}\right)$
$|\vec{A}-\vec{B}|=\sqrt{2} R \sin \left(\frac{\theta}{2}\right)$
$|\vec{A}+\vec{B}|=2 R \sin \left(\frac{\theta}{2}\right)$

Solution

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