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Question

Force between two point charges $q_1$ and $q_2$ placed in vacuum at '$r$' cm apart is $F$. Force between them when placed in a medium having dielectric constant $K=5$ at '$r / 5$' $\mathrm{cm}$ apart will be:

$5 F$
$25 F$
$F / 5$
$F / 25$

Solution

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