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Question

If $f(x)=\frac{4 x+3}{6 x-4}, x \neq \frac{2}{3}$ and $(f \circ f)(x)=g(x)$, where $g: \mathbb{R}-\left\{\frac{2}{3}\right\} \rightarrow \mathbb{R}-\left\{\frac{2}{3}\right\}$, then $(g ogog)(4)$ is equal to

$-4$
$\frac{19}{20}$
$-\frac{19}{20}$
4

Solution

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