Question
If the system of linear equations
$$\begin{aligned} & x-2 y+z=-4 \\ & 2 x+\alpha y+3 z=5 \\ & 3 x-y+\beta z=3 \end{aligned}$$
has infinitely many solutions, then $12 \alpha+13 \beta$ is equal to
If the system of linear equations
$$\begin{aligned} & x-2 y+z=-4 \\ & 2 x+\alpha y+3 z=5 \\ & 3 x-y+\beta z=3 \end{aligned}$$
has infinitely many solutions, then $12 \alpha+13 \beta$ is equal to