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Question

Four identical particles of mass $m$ are kept at the four corners of a square. If the gravitational force exerted on one of the masses by the other masses is $\left(\frac{2 \sqrt{2}+1}{32}\right) \frac{\mathrm{Gm}^2}{L^2}$, the length of the sides of the square is

4L
3L
2L
$\frac{L}{2}$

Solution

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