The relation between time '$t$' and distance '$x$' is $t=\alpha x^2+\beta x$, where $\alpha$ and $\beta$ are constants. The relation between acceleration $(a)$ and velocity $(v)$ is :

Question

$a=-5 \alpha v^5$

$a=-3 \alpha v^2$

$a=-2 \alpha v^3$

$a=-4 \alpha v^4$

Solution

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