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Question

When a metal surface is illuminated by light of wavelength $\lambda$, the stopping potential is $8 \mathrm{~V}$. When the same surface is illuminated by light of wavelength $3 \lambda$, stopping potential is $2 \mathrm{~V}$. The threshold wavelength for this surface is:

3$\lambda$
9$\lambda$
5$\lambda$
4.5$\lambda$

Solution

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