#39; and mass '$m#39; moves in a circle of radius '$r#39; around an infinitely long line charge of li. Tags and topics: Electric Charges and Fields,Gauss's Law,JEE MAIN,JEE Advanced,JEE Mains,KCET,Laws of Motion,Dynamics of Circular Motion,NCERT,NEET, JEE Main Physics,Class 11 Physics,Class 12 Physi.">
#39; and mass '$m#39; moves in a circle of radius '$r#39; around an infinitely long line charge of li. Tags and topics: Electric Charges and Fields,Gauss's Law,JEE MAIN,JEE Advanced,JEE Mains,KCET,Laws of Motion,Dynamics of Circular Motion,NCERT,NEET, JEE Main Physics,Class 11 Physics,Class 12 Physi.">
#39; and mass '$m#39; moves in a circle of radius '$r#39; around an infinitely long line charge of li. Tags and topics: Electric Charges and Fields,Gauss's Law,JEE MAIN,JEE Advanced,JEE Mains,KCET,Laws of Motion,Dynamics of Circular Motion,NCERT,NEET, JEE Main Physics,Class 11 Physics,Class 12 Physi.">
A particle of charge '$-q$' and mass '$m$' moves in a circle of radius '$r$' around an infinitely long line charge of linear charge density '$+\lambda$'. Then time period will be given as :
(Consider $k$ as Coulomb's constant)
$T^2=\frac{4 \pi^2 m}{2 k \lambda q} r^3$
$T=\frac{1}{2 \pi r} \sqrt{\frac{m}{2 k \lambda q}}$
$T=\frac{1}{2 \pi} \sqrt{\frac{2 k \lambda q}{m}}$
$T=2 \pi r \sqrt{\frac{m}{2 k \lambda q}}$
Solution
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