Two integers $x$ and $y$ are chosen with replacement from the set $\{0,1,2,3, \ldots, 10\}$. Then the probability that $|x-y|>5$, is :

Question

$\frac{31}{121}$

$\frac{60}{121}$

$\frac{62}{121}$

$\frac{30}{121}$

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