Question
Let $y=y(x)$ be the solution of the differential equation $\sec x \mathrm{~d} y+\{2(1-x) \tan x+x(2-x)\} \mathrm{d} x=0$ such that $y(0)=2$. Then $y(2)$ is equal to:
Let $y=y(x)$ be the solution of the differential equation $\sec x \mathrm{~d} y+\{2(1-x) \tan x+x(2-x)\} \mathrm{d} x=0$ such that $y(0)=2$. Then $y(2)$ is equal to: