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Question

A particle is placed at the point $A$ of a frictionless track $A B C$ as shown in figure. It is gently pushed towards right. The speed of the particle when it reaches the point B is :

(Take $g=10 \mathrm{~m} / \mathrm{s}^2$).

$2 \sqrt{10} \mathrm{~m} / \mathrm{s}$
$10 \mathrm{~m} / \mathrm{s}$
$\sqrt{10} \mathrm{~m} / \mathrm{s}$
$20 \mathrm{~m} / \mathrm{s}$

Solution

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