Identify product A and product B : - DASH

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Identify product A and product B :

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Step-by-Step Explanation Step 1: Note the Two Different Reaction Conditions The given cyclohexene is reacted with chlorine under two distinct conditions: In the presence of light ($hv$), which supports free-radical chlorination. In the presence of $CCl_4$ (in the dark), which leads to an electrophilic addition reaction. Step 2: Free-Radical Allylic Chlorination (Product A) Under photochemical conditions ($Cl_2$ and $hv$), chlorine radicals are generated. These radicals abstract an allylic hydrogen (the hydrogen on the carbon next to the double bond), resulting in a chlorine substituent on the allylic position. The double bond remains intact. Symbolically: $ \text{Cyclohexene} \xrightarrow[hv]{Cl_2} \text{Allylic-chlorocyclohexene (Product A)} $ Step 3: Electrophilic Addition of Chlorine in $CCl_4$ (Product B) When the reaction occurs in the dark, without radical initiators, chlorine adds across the double bond via an electrophilic addition mechanism. This opens the double bond and forms 1,2-dichlorocyclohexane (a vicinal dichloride). Symbolically: $ \text{Cyclohexene} + Cl_2 \xrightarrow[CCl_4]{} \text{1,2-dichlorocyclohexane (Product B)} $ Step 4: Final Structures Product A: Cyclohexene ring with a chlorine substituted at the allylic position (retaining the double bond). Product B: Cyclohexane ring with two adjacent chlorines (vicinal dihalide). Therefore, under light ($hv$), an allylic substitution occurs (Product A), whereas in the dark, $Cl_2$ adds across the double bond (Product B). Correct Answer:

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