The correct set of four quantum numbers for the valence electron of rubidium atom $(\mathrm{Z}=37)$ is :

Question

$5,1,1,+\frac{1}{2}$

$5,0,0,+\frac{1}{2}$

$5,0,1,+\frac{1}{2}$

$5,1,0,+\frac{1}{2}$

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