$\mathrm{KMnO}_4$ decomposes on heating at $513 \mathrm{~K}$ to form $\mathrm{O}_2$ along with

Question

$\mathrm{K}_2 \mathrm{MnO}_4 ~\& \mathrm{~Mn}$

$\mathrm{MnO}_2 ~\& \mathrm{~K}_2 \mathrm{O}_2$

$\mathrm{K}_2 \mathrm{MnO}_4 ~\& \mathrm{~MnO}_2$

$\mathrm{Mn} ~\& \mathrm{~KO}_2$

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