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Question

$\mathop {\lim }\limits_{x \to {\pi \over 2}} \left( {{1 \over {{{\left( {x - {\pi \over 2}} \right)}^2}}}\int\limits_{{x^3}}^{{{\left( {{\pi \over 2}} \right)}^3}} {\cos \left( {{t^{{1 \over 3}}}} \right)dt} } \right)$ is equal to

$\frac{3 \pi^2}{4}$
$\frac{3 \pi^2}{8}$
$\frac{3 \pi}{4}$
$\frac{3 \pi}{8}$

Solution

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