Question
Identify B formed in the reaction.
$\mathrm{Cl}-\left(\mathrm{CH}_2\right)_4-\mathrm{Cl} \xrightarrow{\text { excess } \mathrm{NH}_3} \mathrm{~A} \xrightarrow{\mathrm{NaOH}} \mathrm{B}+\mathrm{H}_2 \mathrm{O}+\mathrm{NaCl}$
$\stackrel{-}{\mathrm{Cl}}\stackrel{+}{\mathrm{N}} \mathrm{H}_3-\left(\mathrm{CH}_2\right)_4-\stackrel{+}{\mathrm{N}} \mathrm{H}_3 \mathrm{Cl}^{-}$
$\mathrm{H}_2 \mathrm{N}-\left(\mathrm{CH}_2\right)_4-\mathrm{NH}_2$